-80p^2+2560p-17600=0

Solution for -80p^2+2560p-17600=0 equation:

-80p^2+2560p-17600=0

a = -80; b = 2560; c = -17600;
Δ = b2-4ac
Δ = 25602-4·(-80)·(-17600)
Δ = 921600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{921600}=960$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2560)-960}{2*-80}=\frac{-3520}{-160}
=+22
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2560)+960}{2*-80}=\frac{-1600}{-160}
=+10
$